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2x^2-7x-459=0
a = 2; b = -7; c = -459;
Δ = b2-4ac
Δ = -72-4·2·(-459)
Δ = 3721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3721}=61$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-61}{2*2}=\frac{-54}{4} =-13+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+61}{2*2}=\frac{68}{4} =17 $
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